If AB is 5 spaces high and BC is 7 spaces long, you would use the Pythagorean Theorem to get AC, right? Your work would look somewhat like this: But if you used the distance formula, you wouldn't need the 'spaces' because using this formula would give you the sides of all the area all in one equation.
1 is (-4, -1) and 2 is (3, 4)
It doesn't matter if you switched the 1 as (3, 4) and 2 as (-4, -1).
Well, that's what we learned today. It's kind of confusing at first and almost everybody has this "wha..?" face when Ms. Armstrong was explaining it to us...
oh yeah ... Kriszelle, your doing it next...